25C^2+40C+16=

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Solution for 25C^2+40C+16= equation:


Simplifying
25C2 + 40C + 16 = 0

Reorder the terms:
16 + 40C + 25C2 = 0

Solving
16 + 40C + 25C2 = 0

Solving for variable 'C'.

Factor a trinomial.
(4 + 5C)(4 + 5C) = 0

Subproblem 1

Set the factor '(4 + 5C)' equal to zero and attempt to solve: Simplifying 4 + 5C = 0 Solving 4 + 5C = 0 Move all terms containing C to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 5C = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 5C = 0 + -4 5C = 0 + -4 Combine like terms: 0 + -4 = -4 5C = -4 Divide each side by '5'. C = -0.8 Simplifying C = -0.8

Subproblem 2

Set the factor '(4 + 5C)' equal to zero and attempt to solve: Simplifying 4 + 5C = 0 Solving 4 + 5C = 0 Move all terms containing C to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 5C = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 5C = 0 + -4 5C = 0 + -4 Combine like terms: 0 + -4 = -4 5C = -4 Divide each side by '5'. C = -0.8 Simplifying C = -0.8

Solution

C = {-0.8, -0.8}

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